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Simplifying 3[4(y + 3) + -1(y + 5)] = 3(3y + 1) Reorder the terms: 3[4(3 + y) + -1(y + 5)] = 3(3y + 1) 3[(3 * 4 + y * 4) + -1(y + 5)] = 3(3y + 1) 3[(12 + 4y) + -1(y + 5)] = 3(3y + 1) Reorder the terms: 3[12 + 4y + -1(5 + y)] = 3(3y + 1) 3[12 + 4y + (5 * -1 + y * -1)] = 3(3y + 1) 3[12 + 4y + (-5 + -1y)] = 3(3y + 1) Reorder the terms: 3[12 + -5 + 4y + -1y] = 3(3y + 1) Combine like terms: 12 + -5 = 7 3[7 + 4y + -1y] = 3(3y + 1) Combine like terms: 4y + -1y = 3y 3[7 + 3y] = 3(3y + 1) [7 * 3 + 3y * 3] = 3(3y + 1) [21 + 9y] = 3(3y + 1) Reorder the terms: 21 + 9y = 3(1 + 3y) 21 + 9y = (1 * 3 + 3y * 3) 21 + 9y = (3 + 9y) Add '-9y' to each side of the equation. 21 + 9y + -9y = 3 + 9y + -9y Combine like terms: 9y + -9y = 0 21 + 0 = 3 + 9y + -9y 21 = 3 + 9y + -9y Combine like terms: 9y + -9y = 0 21 = 3 + 0 21 = 3 Solving 21 = 3 Couldn't find a variable to solve for. This equation is invalid, the left and right sides are not equal, therefore there is no solution.
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